Question

1. Distance between point (5,-3) and (5.8).

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Answer 1

Answer:

Distance between point (5,-3) and (5.8) is 11 units

Step-by-step explanation:

Given points, (5,-3) and (5,8)

let us take,

$x_{1}$ = 5 --------------- (i)

$y_{1}$ = -3 ---------------(ii)

$x_{2}$ = 5 ---------------(iii)

$y_{2}$ = 8 ---------------(iv)

Now, we have to find the distance between two given points

the formula used for distance is given below-

Distance = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ -----------------(v)

Substitute the equation (i),(ii),(iii),(iv) in equation (v), it becomes-

Distance = $\sqrt{(5-5)^{2}+(8-(-3))^{2}}$

Distance = $\sqrt{(5-5)^{2}+(8+3)^{2}}$

Distance = $\sqrt{(o)^{2}+(11)^{2}}$

Distance = $\sqrt{0+121}$

Distance = $\sqrt{121}$

Distance = 11 units