Question

1. Divide 1870 into three parts in such a way that
half of the first part, one-third of the second part and
one-sixth of the third part are equal.​

Answer 1

$\huge \bf \color{navy}Answer :$

Refer to the attachment !

Answer 2

Step-by-step explanation:

According to d Q's

x+y+z= 1870 then

x/2= 1870*2/11=340

y/3=1870*3/11 = 510

z/6= 1870*6/11=1020

so.. x= 340, y= 510, z = 1020

and x+y+z = 340+510+1020 = 1870