Math, asked by ruksaralizidan, 6 months ago

1. Divide the polynomial x2 - 10x + 21
the following divisors and find the
in each case :
(1) x + 2 (2)x - 3 (3) x + 5
3​

Answers

Answered by ppushpalathasubraman
1

Answer:

2) x-3

Step-by-step explanation:

x2- 10x+ 21

(x-3) (x-7)

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