Question

1) Divide the sum of 65/12 and 8/3 by their difference.
2) If 24 trousers of equal size can be prepared in 54 meters of cloth, what length of the cloth is required for each trouser?

Answer 1

First we have to find the sum (65/12)+(8/3)

LCM of 12 and 3 is 12

Then,

(65×1)/(12×1)=(65/12)

and (8×4)/(3×4)=(32/12)

Now,

=(65+32)/12

=(97/12)

Now find the difference of (65/12)−(8/3)

LCM of 12 and 3 is 12

Then,

(65×1)/(12×1)=(65/12)

(8×4)/(3×4)=(32/12)

Now,

=(65−32)/12

=(33/12)

Now divide (97/12)÷(33/12)

=(97×12)×(12/33)

=(97×12)/(12×33)

=(97×1)/(1×33)

=(97/33)