Math, asked by amanonlyurs1, 2 months ago

{ (1 divided by 3) raised to the power -3 minus (1 divided by 2) raised to the power -3 } divided by (1 divided by 4) raised to the power -3​

Answers

Answered by SiddharthSavant
0

Answer:

 \frac{721 \times 64}{27}

Step-by-step explanation:

The question should look like:

= \frac{(1 \div 3) { }^{ - 3}  - 3 \times (1 \div 2) {}^{ - 3} }{(1 \div 4) {}^{ - 3} }

 \frac{ ( \frac{1}{3})^{ - 3} -  (\frac{3}{2})^{ - 3} }{ (\frac{1}{4}) {}^{ - 3}  }

 \frac{(3) {}^{3} -  (\frac{2}{3}) {}^{3}   }{(4) {}^{3} }

 \frac{27 -  \frac{8}{27} }{64}

 \frac{729 - 8}{27}  \div  \frac{1}{64}

 \frac{721 \times 64}{27}

It cannot be further simplified.

Similar questions
Math, 9 months ago