Math, asked by riyakshirsagar5122, 2 months ago

1)Draw a Circle with centre O and radius 4 cm. Take any four points. A, B, C
and D on the Circle. Draw seg AB, BC, CD and DA. Produce seg AB and take a
find
point E on it such that A-B-E. Now m2 ADC and m2 EBC. Draw your conclusion
and write the statement of the theorem which is verified by above activity.​

Answers

Answered by jagannathsaha113
4

Answer:

Since tangents to a circle is perpendicular to the radius through the point.

∴∠ORD=∠OSD=90

o

It is given that ∠D=90

o

. Also, OR=OS. Therefore, ORDS is a square.

Since tangents from an exterior point to a circle are equal in length.

∴BP=BQ CQ=CR and, DR=DS.

Now,

BP=BQ

⇒ BQ=27 [∵BP=27 cm (Given)]

⇒BC−CQ=27

⇒38−CQ=27

∵ BC=38cm ⇒CQ=11 cm

⇒CR=11 [∵CR=CQ]

⇒CD−DR=11

⇒25−DR=11 [∵CD=25cm]

⇒DR=14 cm

But, ORDS is a square. ⇒ OR=DR=14 cm.

⇒ r=14 cm.

solution

Answer verified by Toppr

4113 ViewsSince tangents to a circle is perpendicular to the radius through the point.

∴∠ORD=∠OSD=90

o

It is given that ∠D=90

o

. Also, OR=OS. Therefore, ORDS is a square.

Since tangents from an exterior point to a circle are equal in length.

∴BP=BQ CQ=CR and, DR=DS.

Now,

BP=BQ

⇒ BQ=27 [∵BP=27 cm (Given)]

⇒BC−CQ=27

⇒38−CQ=27

∵ BC=38cm ⇒CQ=11 cm

⇒CR=11 [∵CR=CQ]

⇒CD−DR=11

⇒25−DR=11 [∵CD=25cm]

⇒DR=14 cm

But, ORDS is a square. ⇒ OR=DR=14 cm.

⇒ r=14 cm.

solution

Answer verified by Toppr

4113 Views

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