1. draw a flowchart to display the odd numbers that are also divisible by 7 between 1 to 50.
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Answer:
first odd no divisible by 7 between 50 and 250
is 7*9=63
Next such no =7*11=77
Now 250=35*7+5
thus such last no=35*7=245
thus sum=7*(9+11+13+15+…………………..+35)……..(1)
This is an AP with a=9 and d=2
Let 35 is nth term in this AP
then 35=9+(n-1)*2
n-1=26/2=13
n=14
Thus sum of series(1)
S=7*14/2(18+13*2)
=49*44
S=2156
Explanation:
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Answered by
0
Answer:
first odd no divisible by 7 between 50 and 250
is 7*9=63
Next such no =7*11=77
Now 250=35*7+5
thus such last no=35*7=245
thus sum=7*(9+11+13+15+…………………..+35)……..(1)
This is an AP with a=9 and d=2
Let 35 is nth term in this AP
then 35=9+(n-1)*2
n-1=26/2=13
n=14
Thus sum of series(1)
S=7*14/2(18+13*2)
=49*44
S=2156
Explanation:
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