Math, asked by sahil865197, 1 month ago

1. Draw a line PQ. Mark two points A and B, both at a distance of 6 cm from PQ and on either side of PQ. Draw two lines parallel to PQ passing through the points A and B.

2 . Draw a line perpendicular to another line AB from any point on AB. On this perpendicular line, choose a point that is 8 cm away from the line PQ. Through O, draw a line CD parallel to AB

3 . Draw an ZABC = 65° such that AB = 6 cm and BC = 8 cm. Draw a line parallel to AB through C. Then draw another line parallel to BC through A. Name the intersecting point D. Measure the line segments AD and CD.

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Answers

Answered by itzmecutejennei
8

Answer:

Given a line PQ with point A outside it.

2. Mark point B on the lie PQ join AB.

3. Taking B as centre, and any radius, draw an arc intersecting PQ at E, and AB at D.

4. With A as centre, and same radius before, draw an arc intersecting AB at F.

5. Open compass to length DE.

6. Now, with F as centre, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.

7. Draw a line m passing through A and H.

Thus m is parallel to PQ, and passing through point A.

∴m∣∣PQ.

hope it helps

Answered by мααɴѕí
13

Answer:

1. Given a line PQ with point A outside it.

2. Mark point B on the lie PQ join AB.

3. Taking B as centre, and any radius, draw an arc intersecting PQ at E, and AB at D.

4. With A as centre, and same radius before, draw an arc intersecting AB at F.

5. Open compass to length DE.

6. Now, with F as centre, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.

7. Draw a line m passing through A and H.

Thus m is parallel to PQ, and passing through point A.

∴m∣∣PQ.

Given: A-line AB=6.2 cm and a point P on it.

Required: To draw a perpendicular arc to AB at point P.

Step of Construction :

(i) With P as a centre and any suitable radius, draw an arc to cut the line AB at points C and D.

(ii) With C and D as centres, draw two arcs of the equal radius (>

2

1

CD) cutting each other at Q.

(iii) Join P and Q.then QP is the required perpendicular to the line AB at the point P

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