(1)
Draw a triangle of sides 3, 4 and 6 centimetres. Draw three different
right triangles of the same area.
Answers
Step-by-step explanation:
Draw a line, let us say, BC of the given length. (Let us say 3 cm)
With B as center, draw an arc with radius 4 (or 6) and with C as center draw another arc with the remaining dimension, that is 6 (or 4). The point where the arcs will intersect would be point A. ABC would be the given triangle.
Through A, draw a line parallel to BC. Draw a line from B perpendicular to BC meeting the parallel line drawn through A at D. If the perpendicular is drawn through C it may meet the parallel line at E. DBC and EBC are the two right angles with the
Repeat the process with BC equal to 4 and the arc lengths of 3 and 6. The same triangle ABC will still be obtained, but the two new right angles will be different since base has changed from 3 to 4 consequently changing the height too.
Repeat the process once more with BC as 6 and arc lengths of 3 and 4. Again there would be the same triangle ABC, but two more right angled triangles.
Thus there will be 3 right angled triangles with the same area and 3 more mirror images of the same.
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