Question

1. Draw any 2 graphs of the following.
i. x+y = 2
ii. 3.x-1=0
iii. 2x + y = 1​

Answer 1

Therefore, the required points are (−1,0),(0,1).

For equation 3x+2y–12=0 or y=

2

12−3x

, we have following points which lie on the line

Plug x=0,4 we get

y=

2

12−0

=6

y=

2

12−12

=0

Answer 2

Step-by-step explanation:

put value of x then corresponding value of y will come