1
E-03
root 3+ 1 upon 2 root 2- root3
Answers
Answered by
1
Step-by-step explanation:
The given equation is:
\frac{1}{2+\sqrt{3}}+\frac{2}{\sqrt{5}-\sqrt{3}}+\frac{1}{2-\sqrt{5}}
2+
3
1
+
5
−
3
2
+
2−
5
1
After rationalising the above equation, we get
=\frac{2-\sqrt{3}}{4-3}+\frac{2\sqrt{5}+2\sqrt{3}}{5-3}+\frac{2+\sqrt{5}}{4-5}
4−3
2−
3
+
5−3
2
5
+2
3
+
4−5
2+
5
=2-\sqrt{3}+\sqrt{5}+\sqrt{3}-2-\sqrt{5}2−
3
+
5
+
3
−2−
5
=00
Hence proved.
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