(1 (e) 1- 11 7 Simplify: 3 8 16 (a) 10+5) 15 Eynress Von
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Step-by-step explanation:
Correct option is
A
3
−2
Re-arranging and grouping the numbers in pairs such that each group
contains a pair of rational numbers with equal denominators, we have
10
−3
+
15
7
+
−20
3
+
10
−9
+
15
13
+
−20
13
=(
10
−3
+
10
−9
)+(
15
7
+
15
13
)+(
−20
3
+
−20
13
)
=(
10
−3
+
10
−9
)+(
15
7
+
15
13
)+(
20
−3
+
20
−13
)
=
10
(−3)+(−9)
+
15
7+13
+
20
(−3)+(−13)
=
10
−12
+
15
20
+
20
−16
=
5
−6
+
3
4
+
5
−4
[Expressing each rational in lowest terms]
=(
5
−6
+
5
−4
)+
3
4
=
5
(−6)+(−4)
+
3
4
=
5
−10
+
3
4
=−2+
3
4
=
3
−6+4
=
3
−2
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