Question

1. E . There are two angles of projection for which the horizontal range is the same. The sum of the maxi- mum heights for these two angles is u? u? (2) g (1 ) 2g u² sin²o (3) u² sin²e 2g (4) g inted with certain need​

Answer 1

Answer:

b

Explanation:

the correctr answer is b because b is coerect one

Answer 2

Answer:

Let the two angles be θ

1

and θ

2

and the projectile velocity be u

Horizontal range R=

g

u

2

sin(2θ

1

)

=

g

u

2

sin(2θ

2

)

=

g

u

2

sin(180−2θ

2

)

⟹ 2θ

1

=180

o

−2θ

2

⟹ θ

2

=90−θ

1

Maximum height attained H

1

=

2g

u

2

sin

2

θ

1

Similarly H

2

=

2g

u

2

sin

2

θ

2

=

2g

u

2

sin

2

(90−θ

1

)

=

2g

u

2

cos

2

θ

1

∴ H=H

1

+H

2

=

2g

u

2

(sin

2

θ

1

+cos

2

θ

2

)

=

2g

u

2