Math, asked by pri4822, 10 months ago

1. Each digit of a natural number is either 2, 3 or 5 and
the number has at least one each of the three digits.
What is the least such number divisible by 18 as well
as 12?​

Answers

Answered by lakshitrajput
0

Answer:

36 is the no. which is divisi bole by 12 and 18 both and also least

Answered by utkarsh2604
0

Answer:

first find the lcm of 12 and 18 .. it is 36 .. now start multiplying it by 2, 3, 4 ...and so on.. you have to do this process till you get the no. which has no other no. than 2,3 or 5 ... 36x7 = 252, so 252 is your answer

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