Question

1. Each of equal sides of an isosceles triangle
is 4cm greater than its height. If the base
of the triangle is 24cm ; calculate the
perimeter and the area of the triangle.​

Answer 1

Answer:

56

2(4+24)=28

2×28=56

Answer 2

Answer:

Perimeter = 64cm

Area = 192cm^2

Step-by-step explanation:

Base = 24cm

Height = xcm

(x+4)^2 = x^2 + (12)^2

x^2 + 8x + 16 = x^2 + (12)^2

8x = x^2 - x^2 + 144 - 16

8x = 128

x = 128/8

x = 16

Perimeter = 24 + 16+ 4 + 16 + 4

Perimeter = 64cm

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

{S = 64/2 = 32 ; A = 24 ; B = 20 ; C = 20}

Area = $\sqrt{32(32-24)(32-20)(32-20)}$

Area = $\sqrt{32*8*12*12}$

Area = $\sqrt{8*4*8*12*12}$

Area = 8*2*12

Area = $192cm^{2}$