Question

1. Each side of a rhombus is 13 cm and one diagonal is 10 cm. Find
(1) the length of its other diagonal (2) the area of the rhombus.​

Answer 1

HOPE IT'S HELPS YOU....... ✌

Answer 2

Step-by-step explanation:

Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.

Given, One diagonal is 10 cm

So, AC = 10

⇒ AO = AC/2 = 5 cm.

Let BO = x and AB = 13 cm.

By Pythagorean theorem ,

c^2 = a^2 + b^2

=> 13^2 = 5^2 + x^2

=> 169 = 25 + x^2

=> x^2 = 169 - 25

=> x^2 = 144

=> x = 12 cm

BO = 12 cm

Diagonal BD = 2 * 12 = 24 cm.

Area = 1/2 * Product of diagonals

        = 1/2 * 10 * 24

        = 120 cm^2

(i)

Length of its diagonal = 24 cm.

(ii)

Area of the rhombus = 120 cm^2

Hope it helps!