1. Earth's magnetic field at the equator is approximately 4X10*calculate earth's dipole moment (Radius of earth = 6.4 x 10 m), 4- 4 x 10" S.I. unit ?
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Answer:
Given:-
Magnetic filed of the earth
\begin{gathered} = 0.4\:G\\\end{gathered}
=0.4G
= 0.4 \times 10 ^{ - 4} \:G=0.4×10
−4
G
Equatorial magnetic field of the earth is given by,
B = \frac{μ_{0}M}{4\pi \: d^{3} }B=
4πd
3
μ
0
M
Where,
\begin{gathered}d = 6400\:km \\ \end{gathered}
d=6400km
d = 6.4 \times 10^{6} md=6.4×10
6
m
Therefore,
Earth's magnetic dipole moment is given by,
M = \frac{Bd^{3} }{10 ^{ - 7} }M=
10
−7
Bd
3
M = \frac{(0.4 \times 10 ^{ - 4}) \times (6.4 \times 10 ^{6})^{3} }{10^{ - 7} }M=
10
−7
(0.4×10
−4
)×(6.4×10
6
)
3
M = 1.05 \times 10^{23} Am^{2}M=1.05×10
23
Am
2
_____________
\bold{Final\:answer:-}Finalanswer:−
M = 1.05 \times 10^{23} Am^{2}M=1.05×10
23
Am
2
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