1 erg =......joule? find by using n2=n1 [m1/m2]^a [l1/l2]^b [t1/t2]^c
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Answer:
10^-7 joule
Explanation:
10^7 erg = 1 loule
1 erg= 1/10^7 Joule
= 10^-7 joule
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