Physics, asked by sakshi0412, 5 months ago

1 erg =......joule? find by using n2=n1 [m1/m2]^a [l1/l2]^b [t1/t2]^c

Answers

Answered by antara83basak

0

Answer:

10^-7 joule

Explanation:

10^7 erg = 1 loule

1 erg= 1/10^7 Joule

= 10^-7 joule

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