Question

1.
Evaluate : 64y^4 + 8y^3 ÷ 4y^3​

Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$= \frac{64y {}^{4} + 8y {}^{3} }{4y {}^{3} } \\ = \frac{4y {}^{3} (16y {}^{} + 2)}{4y {}^{3} } \\ =$

$\huge{\mathcal{\blue{\implies{\underline{16y+2}}}}}$

Answer 2

Answer:

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