1.Evaluate cos45/sec30+cosec 60?2.if cosec=root of n+1 find cos teeta?please answer these 2 q
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1. = 1/√2÷2/√3+2/√3
=1/√2÷4/√3
= √3/4√2
2. cosecФ=√n+1
sinФ =1/√n+1
cos²Ф=1-sin²Ф
cos²Ф=1-1/n+1
= n/n+1
cosФ =√n/n+1
=1/√2÷4/√3
= √3/4√2
2. cosecФ=√n+1
sinФ =1/√n+1
cos²Ф=1-sin²Ф
cos²Ф=1-1/n+1
= n/n+1
cosФ =√n/n+1
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