Math, asked by hjningegowda, 2 months ago


1. Evaluate

(iii) cos 48° - sin 42°​

Answers

Answered by Anonymous
0

Step-by-step explanation:

Valueofcos48°−sin42°

=cos48\degree-sin(90-48\degree)=cos48°−sin(90−48°)

=cos48\degree-cos48\degree=cos48°−cos48°

/* We know that,

Sin(90°-A)=cosA */

=0=0

Therefore,

Value \:of \: cos48\degree-sin42\degree=0Valueofcos48°−sin42°=0

Answered by Anonymous
1

Answer:

Step-by-step explanation:

cos 48° - sin 42°​

=cos(90-42)-sin42

=sin42-sin42

=0

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