Math, asked by furiousmechanzz, 10 months ago

1. Evaluate sin15° cos15° - cos15° - cos75° sin75° 2. Evaluate cot54° ÷ tan36° + tan20° ÷ cot70° - 2 3. Express the following in terms of angle between 0 °and 45° -- cosec 68° + cot72° 4. Evaluate cot²41° ÷ tan²49° - 2sin²75° ÷ cos²15°

Answers

Answered by swapnilsarje17
1

Answer:

(1)sin 15 .cos(90-15) - cos(90-75) .sin 75

=sin 15.sin75 - sin 15 .sin 75

=0

(2)tan(90-x) = cot(x)

so cot 54 /tan 36 = cot54/ cot 54 =1

||ly for tan20/cot70 = 1

so 1+1-2=0

(3)cosec 68 + cot 75

=cosec (90-22)+cot(90-18)

=sec 22 + ten 18

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