Math, asked by adityaprasad48, 29 days ago

1. Evaluate:
 \sqrt[3]{288 \sqrt[3]{72 \sqrt[3]{27} } }

Answers

Answered by Anonymous
1

\boxed{\sqrt[3]{288\sqrt[3]{72\sqrt[3]{27}}}=12}

Explanation:

Now, \sqrt[3]{288\sqrt[3]{72\sqrt[3]{27}}}

=\sqrt[3]{288\sqrt[3]{72\sqrt[3]{3\times 3\times 3}}}

=\sqrt[3]{288\sqrt[3]{72\times 3}}

=\sqrt[3]{288\sqrt[3]{2\times 2\times 2\times 3\times 3\times 3}}

=\sqrt[3]{288\times 2\times 3}

=\sqrt[3]{2\times 2\times 2\times 2\times 2\times 3\times 3\times 2\times 3}

=2\times 2\times 3

=12

Remember:

\sqrt[3]{a\times a\times a}=a

Answered by anusriyadav11
0

Answer:

here is the answer. hope it helps

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