Question

1) Evaluate the following
1) log32​

Answer 1

Answer:

log 32 = 1.50514997832

log 32 = log 2 ^(5 ) =  5  log  2 ≈5 ⋅ 0.30103 = 1.50515

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Answer 2

Answer:

$therefore \\ log(2) = 0.30103\\ log(32) = log( {2}^{5} ) \\ = 5log2 = 5 \times 0.30103 \\ \\answer \: \: \: = 1.50515$