Question

1 Evaluate : x ²-2 dx x² ta 0​

Answer 1

Step-by-step explanation:

We know that, ∫

a

2

+x

2

dx=

2

x

a

2

+x

2

+

2

a

2

log∣x+

x

2

+a

2

∣+C

∴∫

1+x

2

dx=

2

x

1+x

2

+

2

1

log∣x+

1+x

2

∣+C

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