Question

1. Evaluate.

x³+y³+z³-3xyz.
when x= -2.
y= -1.
z=3.

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Answer 1

Answer:

By using identity

x^3 + y^3 + z^3 -3xyz = (x + y + z) (x^2 + y^2 + z^2 - xy - yz - zx)

ans. 6

Step-by-step explanation:

As here x+y+z = 0

Hence x^3 + y^3 + z^3 = 3xyz

= (-2)×(-1)×3

= 6

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