Question

1) Examine which of the polynomial 1,-1 ,-3 are zeroes of the polynomial
p(x)=2x⁴+9x³+11x²+4x-6

2) Exponent form of 2√7 is ___

3) Addition of two irrational number is equal to_____
1) Rational
2) Irrational
3) Integers
4) whole number​

Answer 1

Answer:

irrational is the correct answer

Answer 2

Answer:

$1) \: \: \: \: p(x) = 2 {x}^{4} + 9 {x}^{3} + 11 {x}^{2} + 4x - 6 \\ p(1) = 2 {(1)}^{4} + 9 {(1)}^{3} + 11 {(1)}^{2} + 4(1) - 6 \\ = (2 \times 1) + (9 \times 1) + (11 \times 1) + 4 - 6 \\ = 2 + 9 + 11 + 4 - 6 \\ = \: \: \underline{ \underline{20}} \\ \\ p(x) = 2 {x}^{4} + 9 {x}^{3} + 11 {x}^{2} + 4x - 6 \\ p( - 1) = 2 {( - 1)}^{4} + 9 {( - 1)}^{3} + 11 {( - 1)}^{2} + 4( - 1) - 6 \\ = (2 \times 1) + (9 \times ( - 1)) + (11 \times 1) - 4 - 6 \\ = 2 - 9 + 11 - 4 - 6 \\ = \: \: \underline{ \underline{ - 6}} \\ \\ p(x) = 2 {x}^{4} + 9 {x}^{3} + 11 {x}^{2} + 4x - 6 \\ p( - 3) = 2 {( - 3)}^{4} + 9 {( - 3)}^{3} + 11 {( - 3)}^{2} + 4( - 3) - 6 \\ =(2 \times 81) + (9 \times ( - 27)) + (11 \times 9) + (4 \times - 3) - 6 \\ = 162 + ( - 243) + 99 + ( - 12) - 6 \\ = 162 - 243 + 99 - 12 - 6 \\ = \: \: \underline{ \underline{0}} \\ \\ \: \: \: \large{ \color{brown}{∴ \: \: \: \: p( - 3) = 2 {x}^{4} + 9 {x}^{3} + 11 {x}^{2} + 4x - 6 = 0}} \\ \\ 2) \: \: \: \: 2 \sqrt{7} \\ = \sqrt{ {2}^{2} \times 7 } \\ = \sqrt{4 \times 7} \\ = \: \: \: \large{ \color{brown} \underline{ \underline{ \sqrt{28}}}} \\ \\ 3) \: \: \: \large{ \color{brown}{ (2) \: \: Irrational}}$