1.Expand(1÷x + y÷3 ) 3
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Question
(1÷ x + y÷ 3 ) ³
(1/x + y/3)³
Solution
By using this identity
(a+b)³ = a³ + b³ + 3 ab (a+ b)
(1/x+ y/3)³
=> (1/x)³+ (y/3)³ + 3× 1/x × y/3 (1/x + y/3)
=> 1/x³ + y³/27 + 3/x × y/3 (1/x + y/3)
=> 1/x³ + y³/27 + y/x(1/x + y/3)
=> 1/x³ + y³/27 + y/x² + y²/3x
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