Question

1. Expand (100) root 3
using
identity.
2. prove that (a+b)whole 3 = a cube +3a²b+3ab whole 2 +b whole 3
3.
Expand (2a+3b)
using
identi​

Answer 1

Answer:

3)8a+36a2b+54ab2+27b

Step-by-step explanation:

(a+b)3=a3+3a2b+3ab2+b3

=(2a)3+{3×(2a)2×3b}+{3×2a×(3b)2}+3b3

=8a+36a2b+54ab2+27b

Answer 2

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