Question

1. Expand :
$(2x + \frac{1}{3x} )cube \\ \:$
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Answer 1

Answer:

$(2x + \frac{1}{3x} ) {}^{3} \\ (2x) {}^{3} +( \frac{1}{3x} ) {}^{3} + 3(2x) {}^{2} ( \frac{1}{3x} ) + 3(2x)( \frac{1}{3x} ) {}^{2} \\ 8x {}^{3} + \frac{1}{27x {}^{3} } + 3(4x {}^{2} )( \frac{1}{3x} ) + 3(2x)( \frac{1}{9x {}^{2} } ) \\ 8x {}^{3} + \frac{1}{27x {}^{3} } + 4x + \frac{2}{3x}$