Math, asked by gdxinha, 19 hours ago

1) Expansion of (1+x)^-1 is ​

Answers

Answered by rs7287035
0

Answer:

(1 + x)^-1 = 1 - x + x² - x³

Step-by-step explanation:

(1 + x)^-n = 1 - nx + n(n+1) x²/ 2!

- n(n+2) (n+2) x³ / 3!

(1+x)^-1 = 1 - 1 . x + 1 . 2 x²/ 2! - 1 . 2 . 3 x³ /3!

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