Question

1.
Explain the action of dilute hydrochloric acid on the following with chemical equations
a) Magnesium ribbon b) Sodium hydroxide c) Crushed egg shells
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Answer 1

A)2HCL+2MG=MGCL2+H2

B)HCL+NAOH=H20+NACL

C)HCL+CACO3=CACL2+H20+CO2

Answer 2

Answer:-

Dil. Hydrochloric acid reacts with the following substances in this way:-

• Magnesium ribbon + HCl

Mg + HCl ---> MgCl2 + H2

( Metals react with acid to form metal salts and hydrogen gas. )

• Sodium Hydroxide + HCl

NaOH + HCl ---> NaCl + H2O

( Bases react with acids to form salt and water. Such a reaction is also called neutralization reaction. )

• Calcium Carbonate + HCl

CaCO3 + HCl ---> CaCl2 + CO2 + H2

( The calcium carbonate which is present in egg shells react with hydrochloric acid to form calcium chloride, carbon dioxide and hydrogen gas. One can check the presence of carbon dioxide by passing the gas produced in this reaction through lime juice. If the lime juice turns milky, carbon dioxide is present. )

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