Question

1) explain why a body weighs more at the poles than at the equator of earth?
Two stones of masses 1 kg and 5 kg are released from the top of Qutab-minar. Which stone
will reach the ground first ? If air resistance is not negligible then ?
Calculate the value of g at an altitude equal to the radius of earth.
2) Calculate the acceleration due to gravity on the surface of the moon if the mass of the moon is
7.36x1022 kg and radius is 1740 km. What will be the weight of a body of mass 10 kg on the
moon? Assume the value of G (6.67 x 10-11 Nm?/ kg).
3(Acceleration due to gravity on the surface of the earth is 9.8 m s? Find its value.(given R =6400km)
(a) at a depth of 2000 km
(b) at a height of 500 km

4)Calculate the value of the acceleration due to gravity at a place 3200 km above the surface of the
earth.
5) The acceleration due to gravity at a place is 0.2 m/s2. Find its height above the earth's surface.

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Answer 1

Answer:

The first question answer would be that 5 kg stone will come down first.

Answer 2

Answer:

Explanation:

➡️the earth is not a perfect square, but it is flattened at the poles. The distance between the equator and the center of the earth and the poles therefore the force of gravitation is more at the poles than at the equator...

the stone with 5 kg bcoz it is heavier to handle for the air.

Gravitational acceleration due to earth at distance r from earth's centre is given by

g = GM/r^2

At height equal to earths diameter

h = 2R

r = R+h = R+2R = 3R

Gravitational acceleration at h=2R

g' = GM/9R^2

g' = g/9

g' = 9.8/9

g' = 1.09 m/s^2.

➡️ i dont know second one..

➡️g = 9.8 m/s^2

R = 6400 km = 6.4×10^6 m

h = 480 km = 4.8×10^5 m

Gravitational acceleration at earth's surface is-

g = GM / R^2

Gravitational acceleration at height h is-

g' = GM / (R+h)^2

g'/g = R^2 / (R+h)^2

g' = gR^2 / (R+h)^2

g' = 9.8×(6.4×10^6)^2 / (64×10^5+4.8×10^5)^2

g' = 9.8 × 0.8653

g' = 8.48 m/s^2.

➡️g = GM/R²

g'= g[R^2/(R+h)^2]

= 9.8(40.96 x 10^12/92.16 x 10^12)

= 9.8 x 4/9

= 4.35 m/s²..

➡️g’ = g * [r / (r + h)]^2

0.2 = 9.8 * [r / (r + h)]^2

[r / (r + h)]^2 = 1/49

r / (r + h) = 1/7

7r = r + h

h = 6r

If radius of earth (r) is 6400km

Height (h) is 6 * 6400km = 38400 km...

Hope it helps..

Brainliest please..☺❤