1.Express (3+i5) (2+6i) into a+ib form
Answer:(3+5i)(2+6i)=Z
=3(2)+3(6i)+2(5i)+(5i)(6i)
=6+18i+10i+30i^2
=6+28i-30
= -24+28i
=a+ib
a=-24 and b=28
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