Question

1. Express 408 as prime factors.

2. Check whether the given values are solution of the equations or not: x² ÷ x + 2 = 0; x=1

3. State Pythagoras theorem​

Answer 1

Step-by-step explanation:

1. Find the LCM of 408 and pick out the prime factors.

2. It is not a solution as after putting the value

LHS (2) is not equal to RHS (0)

3. Hypotenuse square = Perpendicular square + Base square

Answer 2

Answer:

Step-by-step explanation:

1). 408= 2 × 204

204 = 2 × 102

102 = 2 × 51

51 = 3 × 17

408 = 2 × 2 × 2 × 3 × 17 = 2³ × 3 × 17  

2). x² ÷ x + 2 = 0 ⇔ x + 2 = 0 ⇒ x = - 2

x = 1 is NOT a solution of x² ÷ x + 2 = 0

3). If "c" is length of the hypotenuse of right angled Δ, and "a" and "b"

are two other sides of that Δ , then c² = a² + b²