Question

1. Express 81 as the sum of 9 odd numbers

2. Express 100 as the sum of 10 odd numbers

3. Write a Pythagorean triplet whose smallest member is

( i )6. ( ii ) 14

4.

Answer 1

1.    1+3+5+7+9+11+13+15+17 = 81
2. it can be represented
3.i dont know

Answer 2

1) 81 is a square of 9. so just write down odd numbers starting from 1 . Remember to only write 9 odd numbers. Hence 81=1+3+5+7+9+11+13+15+17.
2)100 is a square of 10. So just write down odd no starting from 1. This time we have to write 10 odd no.Hence 100=1+3+5+7+9+11+13+15+17+19.
3)a) Pythagorean triplets are x*x+1, x*x-1 , 2x
So let's put value of 6 as 2x. 2x=6 so here x will be 3.
x*x+1= 3*3+1
=10
x*x-1=3*3-1
=8
Hence triplets are 6,8 and 10 .
Part 2 can also be solved using the same method.
Hope it helps.