1. Express cos83 degrees - sec76 degrees in terms of trigonometric ratios of angles between 0 degrees and 45 degrees. 2. Prove that cos1° cos2° cos3°...cos180° = 0.
Please answer the questions written above...... Only correct and proper answers required......
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Answer:
1).cos 83 - sec 76
sin ( 90 - 83 ) - cosec ( 90 - 76 )
sin 7 - cosec 14 =>(sin 2x = 2 sinx.cosx)
sin 7 - 1/2 sin 7.cos 7
therefore, [2sin^2(7).cos (7)] - 1/2sin 7.cos 7
2).Cos1.cos2.cos3.cos4.........cos90........cos178.cos179.cos180
cos 90 = 0
cos 90.cos90=0
so cos1.cos2.cos3........cos180=0
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(2 sin ^2 . cos 7 - 1) / 2 (sin7.cos7)
Step-by-step explanation:
cos 83 - sec 76
sin ( 90 - 83 ) - cosec ( 90 - 76 )
sin 7 - cosec 14 ..........[ sin 2x = 2 sinx.cosx]
sin 7 - 1/2 sin 7.cos 7
therefore, [2sin^2(7).cos (7)] - 1/2sin 7.cos 7
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