Math, asked by 7718270523das, 11 hours ago

1. Express each number as a product of its prime factors: explain webwith Solution @ 140 (ii) 156 Find the ICM and on (ii) 3825 (iv) 5005 (v) 7429 with solution

Answers

Answered by sumitdhadve88
0

Answer:

6 \times  \\  | >  <  = 43525759 -  + 642 \times 656 \times  - 6 -  +  - 9 {2134 {65}^{?} }^{2} | 35.2 \sqrt{52158}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?} 656 \frac{ { {?}^{2} }^{2} }{?}

Answered by aazamkhan007
0

Answer:

So the required answer is

140 =  {2}^{2}  \times 5 \times 7

156 =  {2}^{2}  \times 3 \times 13

3825 =  {3}^{2}  \times  {5}^{2} \times 17

5005=5×7×11×13

7429=17×19×23

Step-by-step explanation:

(1)

Let’s take 140,

Now 140 can be expressed as 2×2×5×7.

So, 140=22×5×7

(2)

Let’s take 156,

Now 156 can be expressed as 2×2×3×13.

So, 156=22×3×13.

(3)

Let’s take 3825.

Now 3825 can be expressed as 3×3×5×5×17.

So, 3825=32×52×17.

(4)

Let’s take 5005,

Now 5005 can be expressed as 5×7×11×13.

So, 5005=5×7×11×13.

(5)

Let’s take 7429,

Now 7429 can be expressed as 17×19×23.

So, 7429=17×19×23

Similar questions