Question

1. Express each of the following number as a product of its prime factors.
(1) 140 (ii) 156 (ii) 3825 (iv) 5005 (v) 7429​

Answer 1

$\huge\star{\orange{\underline{\underline{\mathbb{EXPLANATION:}}}}}$

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(i) 140

By Taking the LCM of 140, we will get the product of its prime factor.

$\mapsto$Hence, 140 = 2 × 2 × 5 × 7 × 1 = 22 × 5 × 7

(ii) 156

By Taking the LCM of 156, we will get the product of its prime factor.

$\mapsto$Hence, 156 = 2 × 2 × 13 × 3 × 1 = 22 × 13 × 3

(iii) 3825

By Taking the LCM of 3825, we will get the product of its prime factor.

$\mapsto$Hence, 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32 × 52 × 17

(iv) 5005

By Taking the LCM of 5005, we will get the product of its prime factor.

$\mapsto$Hence, 5005 = 5 × 7 × 11 × 13 × 1 = 5 × 7 × 11 × 13

(v) 7429

By Taking the LCM of 7429, we will get the product of its prime factor.

$\mapsto$Hence, 7429 = 17 × 19 × 23 × 1 = 17 × 19 × 23

$\large\star{\red{\tt{\underline{\underline{Hence,solved!}}}}}$

Answer 2

Step-by-step explanation:

(i) 140

By Taking the LCM of 140, we will get the product of its prime factor.

$\rightsquigarrow$ so, 140 = 2 × 2 × 5 × 7 × 1 = 22 × 5 × 7

(ii) 156

By Taking the LCM of 156, we will get the product of its prime factor.

$\rightsquigarrow$ so, 156 = 2 × 2 × 13 × 3 × 1 = 22 × 13 × 3

(iii) 3825

By Taking the LCM of 3825, we will get the product of its prime factor.

$\rightsquigarrow$ so, 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32 × 52 × 17

(iv) 5005

By Taking the LCM of 5005, we will get the product of its prime factor.

$\rightsquigarrow$ so, 5005 = 5 × 7 × 11 × 13 × 1 = 5 × 7 × 11 × 13

(v) 7429

we have to take the LCM of 7429,Then, we will get the product of its prime factor.

$\rightsquigarrow$ so, 7429 = 17 × 19 × 23 × 1 = 17 × 19 × 23