Question

1. f (x)= 3x +4



2.g (x)= x²+3​

Answer 1

Answer:

$f(x) = 3x + 4 = 0 \\ \\ = > x = \frac{ - 4}{3} \\ \\ \\ \\ \\ g(x) = {x}^{2} +3 = 0 \\ \\ = > {x}^{2} = 3 = > x = - \sqrt{3}$

Answer 2

Answer:

f(x)= 3x+4

= f(x) = 3x+4=0

3x= -4

x= -4/3

in the same way 2nd question will be done

hope it's helpful