Question

1. f(x, y) = x² + xyz + z Find fx at (1,1,1)​

Answer 1

SOLUTION

GIVEN

f(x, y, z ) = x² + xyz + z

TO DETERMINE

$\sf{The \: value \: of \: \: f_x \: \: at \: \: (1,1,1)}$

EVALUATION

Here the given function is

f(x, y, z ) = x² + xyz + z

Differentiating both sides partially with respect to x we get

$\sf{f_x(x,y,z) = 2x + yz}$

Hence

$\sf{f_x(1,1,1) = (2 \times 1) + (1 \times 1 )}$

$\sf{ \implies \: f_x(1,1,1) = 2 + 1}$

$\sf{ \implies \: f_x(1,1,1) = 3}$

FINAL ANSWER

$\boxed{ \sf{ \: \: f_x(1,1,1) = 3 \: \: }}$

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Answer 2

Answer:

Step-by-step explanation: