Question

1.
FA
F.
→X
Xo
Calculate the net work done by the force F whose
variation with position has been shown as above.​

Answer 1

Explanation:

From x=−2 mtox= 0m, displacement of the particle is along positive x-direction while force acting on the particle is along negative x-direction. Therefore, work done is negative and given by the area under F-x graph.

∴W=−

2

1

(2)(10)=−10J