1. Factorise: 128x^2-18y^2
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The answer after factorization of 128 x²-18 y² is 2(8 x - 3 y)(8 x + 3 y).
Explanation:
We have the expression:
128 x²-18 y²
We will first take out the common multiple and get that:
2(64 x² -9 y²)
Now we can also write it as:
2[(8 x)² -(3 y)²]
Now we know the property that:
a² - b² =(a - b)(a + b)
Applying the property and simplifying the expression, we get that:
2(8 x - 3 y)(8 x + 3 y)
Therefore, after factorizing the expression 128 x²-18 y², we get 2(8 x - 3 y)(8 x + 3 y).
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