1. Factorise : 16x² + 9y² + 4z² + 24 xy + 12 yz + 16 zx
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Answer:
16x² + 9y² + 4z² + 24 xy + 12 yz + 16 zx
16x² + 9y² + 4z² + 2(12 xy + 6 yz + 8 zx)
(4x)² + (3y)²+ (2z)² +2 [(4x*3y) + (3y*2z)+ (2z*4x)]
= a²+b²+c²+2(ab+bc+ca)
This is equal to
(a+b+c)²
So (4x+3y+2z)²
Hope this helps u :)
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