Question

(1) Factorise:
2x^2 + y^2 + 8z^2 - 2√2xy + 4√2yz - 8xz
Please yaar help kar do. Factorise. ​

Answer 1

( -√2x + y + 2√2z ) ^ 2 ....Ans

Answer 2

Answer:

Factorize: 2x2 + y2 + 8z2 - 2√2xy + 4√2yz - 8xz

Answer:

Given 2x2 + y2 + 8z2 – 2√2xy + 4√2yz – 8xz

Using identity,

(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx

We can say that,

x2 + y2 + z2 + 2xy + 2yz + 2zx = (x + y + z)2

2x2 + y2 + 8z2 – 2√2xy + 4√2yz – 8xz

= (-√2x)2 + (y)2 + (2√2z)2 + (2 × -√2x × y) + (2 × y × 2√2z) + (2 × 2√2 × -√2x)

= (-√2x + y + 2√2z)2

= (-√2x + y + 2√2z)(- √2x + y + 2√2z)

Step-by-step explanation:

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