Question

1.
Factorise : 9-a6 + 2a3b3 – b6​

Answer 1

Answer:

x = a^3, y= b^3

9-a^6+2a^3b^3-b^6

= 9-(x^2-2xy+b^2)

= 3^2 - (x-y)^2

= [3-(x-y)][3+(x+y)]

= (3-x+y)(3+x+y)

now put value of x and y

= (3-a^3+b^3)(3+a^3+b^3)