1. Factorise: (a - b) ^3+ (b-c) ^3 +(c-a)^3
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Let (a-b) =x, (b-c)=y and (c-a)=z
as we know that when x+y+z=0 then x^3+y^3+z^3= 3xyz
Therefore answer is
3(a-b)(b-c)(c-a)
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