Question

1. Factorise: (i) 100x2-49y2 (ü) 9x2y2-121​

Answer 1

Step-by-step explanation:

$100x^{2} -49y^{2}\\= (10x)^{2} - (7y)^{2} \\a^{2} - b^{2} = (a+b)(a-b) \\= (10x+7y)(10x-7y)$

$9x^{2} y^{2} - 121\\= (3xy)^{2} - 11^{2}\\a^{2}-b^{2}=(a+b)(a-b)\\= (3xy+11)(3xy-11)$