Question

1 factorise the following expression .
(i)
${a}^{2} + 8a + 16$


​

Answer 1

$\large{\underbrace{\sf{\red{ Required\:Solution:}}}}$

${a}^{2} + 8a + 16$

${a}^{2} + 4a + 4a + 16$

$=a(a+4)+4(a+4)$

$=(a+4)(a+4)$

$=(a+4)$

$=2$

Answer 2

$\huge \underline \mathfrak \red{Solution}$

a^2+ 8a + 16

=a^2+ 4a + 4a + 16

=a(a+4)+4(a+4)

=(a+4)(a+4)

=(a+4)

=2