Question

1) factorize
1) (x+4) (x-2) 2 (x-8) -37​

Answer 1

Answer:

$(x^2 - 4x + 5) (x^2 - 4x - 33)$

Step-by-step explanation:

$(x + 4) (x - 2)^2 (x - 8) - 37\\\\\mathrm{Rearranging\:the\:terms}\\\\= [(x + 4) (x - 8)]\:[(x - 2)^2] - 37\\= [x^2 - 4x - 32]\:[x^2 - 4x + 4] - 37\\\\\mathrm{Let\:} x^2 - 4x = t\\\\= [t - 32] [t + 4] - 37\\= [t^2 - 28t - 128] - 37\\= t^2 - 28t - 165\\= t^2 - 33t + 5t - 165\\= t (t - 33) + 5 (t - 33)\\= (t + 5) (t - 33)\\\\\mathrm{Substituting\:the\:value\:of\:t}\\\\= (x^2 - 4x + 5) (x^2 - 4x - 33)$

Answer 2

Answer:

(x+4) (x-8) (x-2)2 -37

(a-32) (a+4)-37

(a2-28a-165)

a2-33+5a-165

a(a-33)+5(a-33)

(a+5) (a-33)

(x2-4x+5) (x2-4x-33)